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Free JAMB Past Question for physics

Q.1

If the force and the velocity on a system are each reduced simultaneously by half, the power of the system is


A. Doubled

B. Constant

C. Reduced to a quarter

D. Reduced by half


Correct Answer: option c

Show explanation

1. The formula for power: Power (P) = Force (F) × Velocity (v)


2. Reduced by half:

  1. New Force (F′) = F2\frac{F}{2}
  2. New Velocity (v′) = v/2 v2\frac{v}{2}


3. Calculate the new power (P′):

  1. P′=F′×v′
  2. P′=f2\frac{f}{2} × v2\frac{v}{2}
  3. P′=14FV\frac{1}{4}*FV


4. Compare to original power: Since P=Fv, then P′= 14P\frac{1}{4}*P . The power is reduced to a quarter.


Q.2

What is the phenomenon responsible for the bending of a bimetallic strip when heated?

A. Anomalous expansion of water.

B. Linear expansivity.

C. Volume expansivity.

D. High heat capacity.


Correct Answer: option b

Further reading: Thermal Expansion - Effects and applications

Show explanation

A bimetallic strip is made of two metals with different coefficients of linear expansion. When heated, the metal with the higher linear expansivity expands more than the other. This unequal expansion causes the strip to bend, with the more expansive metal on the outside of the curve. This principle is used in thermostats and thermometers

Q.3

A metal of mass 0.5kg is heated to 100°C and then transferred to a well lagged calorimeter of heat capacity 80JK180JK^{-1} containing water of heat capacity at 15°C. If the final steady temperature of the mixture is 25°C, find the specific heat capacity of the metal.


A. 92JkgK192J kg K^{-1}

B. 286Jkg1K1286 J kg^{-1} K^{-1}

C. 133Jkg1K1133 J kg^{-1} K^{-1}

D. 877Jkg1K1877 J kg^{-1} K^{-1}

Correct Answer: option c

Show explanation

This is a calorimetry problem based on the principle of heat exchange: Heat lost by hot object = Heat gained by cold objects (water and calorimeter).


1. Given values:

  1. Mass of metal (mm​) = 0.5 kg
  2. Initial temp of metal (Tm,i​) = 100°C
  3. Final mixture temp (Tf​) = 25°C
  4. Initial temp of water/calorimeter (Tw,i​,Tcal,i​) = 15°C
  5. Heat capacity of water (Cw​) = 420JK1420 J K^{-1} (This is the total heat capacity, not specific)
  6. Heat capacity of calorimeter (Ccal​) = 80JK180 J K^{-1} (Total heat capacity)


2. Calculate temperature changes:

  1. Temperature change of metal (ΔTm​) = Tm,i​−Tf​=100∘C−25∘C=75∘C=75 K
  2. Temperature change of water (ΔTw​) = Tf​−Tw,i​=25∘C−15∘C=10∘C=10 K
  3. Temperature change of calorimeter (ΔTcal​) = Tf​−Tcal,i​=25∘C−15∘C=10∘C=10 K


3. Apply heat exchange equation:

  1. Heat Lost by Metal = (Heat Gained by Water) + (Heat Gained by Calorimeter)
  2. mm​cm​ΔTm​=Cw​ΔTw​+Ccal​ΔTcal​


4. Substitute values and solve for cm​ (specific heat capacity of the metal):

  1. 0.5×cm​×75=(420×10)+(80×10)
  2. 37.5cm​=4200+800
  3. 37.5cm​=5000
  4. cm​=500037.5133.33Jkg1K1\frac{5000}{37.5}≈133.33 J kg^{-1} K^{-1}



Q.4

Which of the following is a direct application of the principle of conservation of linear momentum?

A. A rocket propelled into space.

B. A car moving on a straight road.

C. A ball bouncing off a wall.

D. A satellite orbiting the Earth.


Correct Answer: option a

Further reading: Motion - Conservation of linear momentum

Show explanation

The principle of conservation of linear momentum states that in the absence of external forces, the total momentum of a system remains constant. A rocket uses this principle by expelling hot gases at high velocity in one direction. To conserve the total momentum of the rocket-gas system, the rocket itself gains momentum in the opposite direction, propelling it forward.

Q.5

In the context of the atomic structure, which of the following is true about isotopes of an element?

A. They have the same number of neutrons but different numbers of protons.

B. They have the same number of electrons but different numbers of protons.

C. They have the same number of protons but different numbers of neutrons.

D. They have different numbers of protons, neutrons, and electrons.

Correct Answer: option c

Further reading: Elementary Modern Physics - Isotopes of an element

Show explanation

Isotopes of an element are atoms that have the same number of protons (atomic number) but a different number of neutrons. Because they have the same number of protons, they belong to the same chemical element. The difference in the number of neutrons results in different mass numbers. For example, Carbon-12 and Carbon-14 are isotopes of carbon, both having 6 protons, but Carbon-12 has 6 neutrons while Carbon-14 has 8 neutrons.

Q.6

A radioactive element has a half-life of 10 years. What fraction of the original sample will be remaining after 30 years?

A. 1/2

B. 1/4

C. 1/8

D. 1/16


Correct Answer: option c

Further reading: Elementary Modern Physics - Half-life and decay constant

Show explanation

The half-life is the time it takes for half of the radioactive atoms in a sample to decay. In 30 years, there will have been 3 half-lives (30 years / 10 years/half-life = 3 half-lives). After the first half-life, 1/2 of the sample remains. After the second, 1/2 of that remains, which is 1/4 of the original. After the third half-life, 1/2 of the 1/4 remains, which is 1/8 of the original sample

Q.7

A person is standing in an elevator that is stationary. What is the reading on the scale?

A. Greater than the person's normal weight.

B. Less than the person's normal weight.

C. Equal to the person's normal weight.

D. Zero.


Correct Answer: option c

Further reading: Gravitational field - Distinction between mass and weight

Show explanation

When the elevator is stationary, there is no acceleration. According to Newton's first law, the net force on the person is zero. The forces acting on the person are their weight (W) acting downwards and the normal force (N) from the scale acting upwards. Therefore, NW=0N - W = 0 , which means N=WN = W . The reading on the scale, which is the normal force, is equal to the person's normal weight

Q.8

What is the main disadvantage of echoes and reverberations in an enclosed space?

A. They make the sound louder.

B. They make it difficult to hear clearly what is being said.

C. They prevent sound from traveling long distances.

D. They increase the speed of sound.

Correct Answer: option b

Further reading: Propagation of Sound Waves - Disadvantages of echoes and reverberations

Show explanation

In an enclosed space, such as a large hall or a stadium, sound waves can reflect off the walls, ceiling, and other surfaces. When these reflections arrive after the direct sound, they are called echoes. When the reflections are very rapid and merge with the original sound, it is called reverberation. Both of these phenomena interfere with the clarity of speech and music, making it difficult to understand what is being said.

Q.9

A traveling wave moving from left to right has an amplitude of 0.15m, a frequency of 550 Hz and a wavelength of 0.01m. The equation describing the wave is


A.9 y=0.15sin200π(x−5.5t)

B. y=0.15sinπ(0.01x−5.5t)

C. y=0.15sin5.5π(x−200t)

D. y=0.15sinπ(550x−0.01t)

Correct Answer: option a

Show explanation

1. General wave equation: For a wave moving in the positive x-direction is y=Asin(kx−ωt), where A is amplitude, k is wave number, and ω is angular frequency.


2. Extract given values:

  1. Amplitude (A) = 0.15 m
  2. Frequency (f) = 550 Hz
  3. Wavelength (λ) = 0.01 m


  1. Calculate wave speed (v):
  2. v=fλ=550 Hz×0.01 m=5.5 m/s

3. Calculate angular frequency (ω):

  1. ω=2πf=2π×550=1100π rad/s


4. Calculate wave number (k):

  1. k=2πλ=2π0.01=200πrad/m\frac{2π}{λ}=\frac{2π}{0.01}=200π rad/m


5. Substitute values into the general equation:

  1. y=0.15sin(200πx−1100πt)


6. Factor out 200π to match option A's format (y=Asin[k(x−vt)], where k=200π and v=5.5):

  1. y=0.15sin[200π(x−(1100π/200π)t)]
  2. y=0.15sin[200π(x−5.5t)]


Q.10

A catapult used to hold a stone of mass 500g is extended by 20cm with an applied force F. If the stone leaves with a velocity of 40ms140ms^{-1}, the value of F is


A. 4.0×102 N

B. 4.0×103 N

C. 2.0×103 N

D. 4.0×102 N

Correct Answer: option c

Show explanation

1. Identify given values:

  1. Mass (m) = 500g = 0.5 kg
  2. Extension (x) = 20cm = 0.2 m
  3. Final velocity (v) = 40 m/s


2. Apply Work-Energy Theorem: The work done by the catapult equals the change in kinetic energy of the stone.

  1. Work Done (W) = Force (F) × Distance (x)
  2. Kinetic Energy (KE) = 12mv2\frac{1}{2}mv^2
  3. Therefore, FX=12mv2F*X=\frac{1}{2}mv^2


3. Substitute values and solve for F:

  1. F0.2=120.5402F*0.2=\frac{1}{2}*0.5*40^2
  2. F×0.2=0.25×1600
  3. F×0.2=400
  4. F=4000.2=2000NF=\frac{400}{0.2}=2000 N
  5. \therefore F=2.0×103 N


Q.11

Which of the following is a vector quantity?

A. Speed

B. Mass

C. Work

D. Momentum


Correct Answer: option d

Further reading: Scalars and Vectors - Definition of scalar and vector quantities

Show explanation

A vector quantity is a physical quantity that has both magnitude and direction. Momentum is a vector quantity, as it is the product of mass (a scalar) and velocity (a vector), and it has a direction. Speed, mass, and work are all scalar quantities, having only magnitude.

Q.12

The velocity ratio of a machine is 5 and its efficiency is 75%. What effort would be needed to lift a load of 150N with the machine?


A. 50 N

B. 40 N

C. 30 N

D. 20 N

Correct Answer: option b

Show explanation

Getting the value

  1. Velocity Ratio (VR) = 5
  2. Efficiency n=75%=75100=0.75n = 75\% = \frac{75}{100} = 0.75
  3. Load = 150 N

Find Mechanical Advantage (MA):

  1. η=MAVRMA=ηVR=0.755=3.75η=\frac{MA}{VR}​⇒MA=η⋅VR=0.75 ⋅ 5=3.75

Find Effort:

  1. Effort=LoadMA=1503.75=40NEffort=\frac{Load}{MA}​=\frac{150​}{3.75}=40N

Q.13

Which of the following is a unit of energy?

A. Watt (W)

B. Newton (N)

C. Joule (J)

D. Pascal (Pa)


Correct Answer: option c

Further reading: Work, Energy and Power - Definition of work, energy and power

Show explanation

The Joule (J) is the SI unit of energy and work. The Watt (W) is the unit of power (energy per unit time). The Newton (N) is the unit of force, and the Pascal (Pa) is the unit of pressure.

Q.14

What is the phenomenon where a body continues in its state of rest or uniform motion in a straight line unless acted upon by an external force?

A. Momentum

B. Impulse

C. Inertia

D. Force


Correct Answer: option c

Further reading: Motion - Newton's laws of motion: inertia

Show explanation

This is the definition of inertia, which is the property of a body to resist changes in its state of motion. It is the basis for Newton's first law of motion. A more massive body has more inertia

Q.15

What is the principle behind the operation of an optical fibre?

A. Reflection

B. Refraction

C. Total internal reflection

D. Dispersion


Correct Answer: option c

Further reading: Refraction of Light Through at Plane and Curved Surfaces - Critical angle and total internal reflection

Show explanation

An optical fibre is a device that transmits light over long distances by making use of the principle of total internal reflection. The fibre consists of a core with a high refractive index surrounded by a cladding with a lower refractive index. When light enters the core at a shallow angle, it is reflected repeatedly off the boundary between the core and cladding, staying within the fibre as it travels.

Q.16

In a parallel-plate capacitor, if the potential difference across the plates is doubled while keeping the plate separation constant, what happens to the energy stored in the capacitor?

A. It is halved.

B. It is doubled.

C. It remains the same.

D. It is quadrupled.


Correct Answer: option d

Further reading: Capacitors - Energy stored in a capacitor

Show explanation

The energy stored in a capacitor (E) is given by the formula E=12CV2E = \frac{1}{2}CV^2 , where $ is the capacitance and $V$ is the potential difference. The capacitance of a parallel plate capacitor is given by C=ϵAdC = \frac{\epsilon A}{d} , which is constant if the area (A) and separation ($d$) are constant. If the potential difference (V) is doubled, the new potential difference is 2V. The new energy stored will be Enew=12C(2V)2=12C(4V2)=4(12CV2)=4EE_{new} = \frac{1}{2}C(2V)^2 = \frac{1}{2}C(4V^2) = 4(\frac{1}{2}CV^2) = 4E . Therefore, the energy stored is quadrupled.

Q.17

A body is projected horizontally from a height of 80 m with an initial velocity of 20 m/s. How long does it take for the body to hit the ground? (Take g = 10 m/s²)

A. 2 s

B. 4 s

C. 8 s

D. 16 s


Correct Answer: option b

Further reading: Motion - Projectiles: calculation of time of flight from a height

Show explanation

The horizontal and vertical motions of a projectile are independent of each other. The time it takes for the body to hit the ground is determined by the vertical motion. The equation for vertical motion is h=ut+12gt2h = ut + \frac{1}{2}gt^2 . Since the body is projected horizontally, the initial vertical velocity (u) is 0 m/s. So, the equation simplifies to h=12gt2h = \frac{1}{2}gt^2 . Rearranging to solve for tt , we get t2=2h/gt^2 = 2h/g . Substituting the values, t2=(2×80)/10=160/10=16t^2 = (2 \times 80) / 10 = 160 / 10 = 16 . Therefore, t=16=4t = \sqrt{16} = 4 s.

Q.18

Total internal reflection occurs when light moves from


A. air to water

B. water to glass

C. a less dense medium to a dense medium

D. a dense medium to a less dense medium

Correct Answer: option d

Show explanation

Total Internal Reflection (TIR) is a phenomenon where a light ray is completely reflected back into the first medium. This occurs only under two specific conditions:

  1. The light must travel from an optically denser medium (higher refractive index) to an optically rarer medium (lower refractive index).
  2. The angle of incidence must be greater than the critical angle for that specific interface.



Q.19

What is the primary method of heat transfer from the Sun to the Earth?

A. Conduction

B. Convection

C. Radiation

D. Absorption


Correct Answer: option c

Further reading: Heat Transfer - Conduction, convection and radiation as modes of heat transfer

Show explanation

Radiation is the transfer of heat through electromagnetic waves, and it does not require a material medium. The space between the Sun and the Earth is a vacuum, so heat can only be transferred by radiation. Conduction and convection require a medium for transfer

Q.20

What is the reason for the anomalous expansion of water?

A. It expands when heated from 0°C to 4°C.

B. It expands when heated from 4°C to 100°C.

C. It contracts when heated from 0°C to 4°C.

D. It contracts when cooled from 4°C to 0°C.


Correct Answer: option c

Further reading: Thermal Expansion - Anomalous expansion of water

Show explanation

Most liquids expand when heated and contract when cooled. However, water behaves anomalously between 0°C and 4°C. When heated from 0°C to 4°C, water contracts and its density increases, reaching its maximum density at 4°C. When heated further above 4°C, it expands like a normal liquid

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